Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75 kg and 80 kg respectively. What is the gravitational force between them?

Explanation

Given :
r = 1 m, `m_(1)=75kg,m_(2)=80kg`
and `G=6.67xx10^(-11)Nm^(2)kg^(2)`
According to Newton.s law
`F=(Gm_(1)m_(2))/(r^(2))`
`F=(6.67xx10^(-11)xx75xx80)/(1^(2))N`
`=4.002xx10^(-7)N`
The gravitational force between Mahendra and Virat is `4.002xx10^(-7)N` This is a very small force.