Calculate the gravitational force due to the earth on Mahendra in the earlier example.

Explanation

Given :
Mass of earth `=m_(1)=6xx10^(24)kg`
Radius of the earth = `R=6.4xx10^(6)m`
Mahendra.s mass `=m_(2)=75kg`
`G=6.67xx10^(-11)Nm^(2)//kg^(2)`
Using the force law, the gravitational force on Mahendra due to earth is given by this force is `1.83xx10^(9)` times larger than the gravitational force between Mahendra.s and Virat.
`F=(Gm_(1)m_(2))/(R^(2))`
`F=(6.7xx10^(-11)xx75xx6xx10^(24))/(6.4xx10^(6))^(2)N`
`=(3001.5)/(40.96)xx(10^(13))/(10^(12))`
`73.27xx10^(1)`
= 732.7 N
F = 733 N
The gravitational force due to the earth on Mahendra is 733 N.