What happens when KI solution is added to acidified `K_2Cr_2O_7` solution?

Explanation

When KI solution is added to acidified `K_(2) Cr_(2) O_(7)` solution, it gives `Cr^(3+) and I_(2)` as follows :
`Cr_(2) O_(7)^(2-) + 14 H^(+) + 6I^(-) to 2Cr^(3+) + 3I_(2) + 7 H_(2) O " or " K_(2) Cr_(2) O_(7) + 7 H_(2) SO_(4) + 6 KI to underset("(III) sulphate") underset("Chromium ")(Cr_(2) (SO_(4))_(3))+ 7H_(2) O + 4 K_(2) SO_(4) + 3I_(2)`