What is the equivalent mass of `KMnO_(4)` in alkaline solution ? Explain.

Explanation

The reaction of `KMnO_(4)` with an alkali is given as follows :
`2KMnO_(4) + 2KOH to 2K_(2) MnO_(4) + H_(2)O + [O]`
`rArr MnO_(4)^(-) + e^(-) to MnO_(4)^(2-)`
In an alkaline medium , the oxidation number of Mn changes from + 7 to + 6 . Therefore , one electron is required for reduction
The molecular mass of `KMnO_(4)` is 158 g/mol.
`:.` The equivalent mass of `KMnO_(4)` is.
`=("Molecular mass")/(1) = (158)/(1) = 158 eq^(-1)`