A charge q is placed at the centre of an imaginary cubical body. Electric flux through any one of its faces is

Options

A. `(q)/(epsi_(0))`
B. `(6q)/(epsi_(0))`
C. `(q)/(6epsi_(0))`
D. `(q)/(3 epsi_(0))`

Answer

C

Explanation

By Gauss.s theorem, total electric flux linked with a closed surface is given by `phi= (q)/(epsi_(0))`, where q is total charge enclosed by the closed surface.
`thereofre` Total electric flux linked with cube, `phi= (q)/(epsi_(0))`
As charge is at centre, therefore electric flux is symmetrically distributed through all six faces.
Flux linked with each face `=(1)/(6) phi = (1)/(6) xx (q)/(epsi_(0)) = (q)/(6 epsi_(0))`