What is the electric flux through a closed surface enclosing an electric dipole?

Explanation

As, the total charge of a dipole `(+q-q =0)` is zero. So, from Gauss.s theorem,
`phi= (q)/(epsi_(0))= (0)/(epsi_(0))= 0`
So, the flux through a closed surface enclosing an electric dipole is zero.