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State Gauss.s law in electrostatics....

State Gauss.s law in electrostatics.

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The surface integral of the electric field intensity over any closed surface (called Gaussian surface) in free space is equal to `(1)/(epsi_(0))` times the net charge enclosed within the surface.
`phi_(E )= underset(s)oint E.dS = (1)/(epsi_(0)) underset(i=1)overset(n)Sigma q_(i)= (q)/(epsi_(0))`
where, `q= underset(i=1)overset(n)Sigma q_(i)` is the algebraic sum of all the charges inside the closed surface. Hence, total electric flux over a closed surface in vacuum is `(1)/(epsi_(0))`. Times the total charge within the surface regardless of how the charges may be distributed.
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