The electric potential at a point at a distance of 2m from a point charge of `0.1mu C` is 450V. The electric field at this point will be….N/C.

Explanation

Given, `V = 450V, r=2m and q= 0.1mu C`
Since, electric field, `|E| = (dV)/(dr)= (450)/(2)= 225V//m`
= 225N/C