A hollow spherical conductor of radius 2m carries a charge of `1nC`. The electric potential at the centre of the spherical conductor is

Options

A. 0
B. `4.5V`
C. `1.5V`
D. `2.25V`

Answer

B

Explanation

Given, radius of hollow spherical conductor, r=2m
Charge, `q=1nC = 1 xx 10^(-9)C`
The electric potential at the centre of the spherical conductor is given by
`V= (q)/(4pi epsi_(0)r)`
`=(9 xx 10^(9) xx1 xx 10^(-9))/(2) [ "here" (1)/(4pi epsi_(0)) =9 xx 10^(9)]`
`therefore V= 45V`