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The electric potential V as a function o...

The electric potential V as a function of distance x(in metre) is given by `V= (2x^(2) + 5x-9)V`
The value of electic field at x=1m would be

A

9V/m

B

`-9V//m`

C

`-7V//m`

D

`-2V//m`

Text Solution

Verified by Experts

The correct Answer is:
B
`therefore E= - (dV)/(dx)`
Given, electric potential, `V= (2x^(2) + 5x-9)V`
The value of electric field at x=1m is
`E= - (d)/(dx) [2x^(2) + 5x-9] = -[4x+5]= - 9V//m`
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