A region in an electric field is given by the potential function `V(x)= ax^(2) + b`, where V is expressed in volt and x in metre. Find out the units of a and b.

Explanation

Given `V(x)= ax^(2) +b`
where, x is in metre and V is in volt. Here, unit of b= unit of V
`rArr` unit of b= volt or `JC^(-1)` There is a summation in equation, hence unit of b= unit of `ax^(2)`
`rArr a ("metre")^(2)= JC^(-1)`
`rArr a= JC^(-1) m^(-2)`
So, unit of `b= JC^(-1) and a=JC^(-1) m^(2)`