In SI unit, V at a point in an electric field is given by `V= -(6)/(x)+2`. Find the value of E in the field at the point (2, 0,0).

Explanation

Given, `V= - (6)/(x) + 2`
`therefore |E| = |-(dV)/(dx)|= |-((-6)/(x^(2)) + 0)| rArr E= (6)/(x^(2))`
Given point is (2, 0,0), i.e., x= 2 units.
So, `E= (6)/(2^(2))=1.5` units.