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The distance between the plates of a par...

The distance between the plates of a parallel plate capacitor of capacitance C Is doubled Its new capacitance will be

A

2C

B

`1/2C`

C

`C^(2)`

D

4C

Text Solution

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The correct Answer is:
B

Capacitance of parallel plate capacitor,
`C=(epsilon_(0)A)/(d)`
where, A = area of plates
and d = distance between plates.
i.e. `C prop(1)/(d)`
If the distance between the plates of a parallel plate capacitor of capacitance C is doubled, then its new capacitance will be
`C.=(1)/(2)C`
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