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Four capacitors each of capacitance 0.5m...

Four capacitors each of capacitance `0.5muF` are connected in parallel. The resultant capacitance of the combination is

A

`0.5muF`

B

`0.125muF`

C

`2muF`

D

`4muF`

Text Solution

Verified by Experts

The correct Answer is:
C
`C_("eq")=C_(1)+C_(2)+C_(3)+C_(4)`
`0.5+0.5+0.5+0.5=2muF`
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