For a parallel plate capacitor , area of each plate is `1m^(2)` and the separation between the plates is 1 mm. The space between the plates contain air Find out the capacitance of this capacitor.
(Take, `epsilon_(0)=8.85xx10^(-12)` SI units)

Explanation

Given, `A=1m^(2),d=1" mm "=1xx10^(-3)m`,
`epsilon=8.85xx10^(-12)"C"^(2)"N"^(-1)"m"^(-2)" and "C=?`
`:.` Capacitance, `C=(epsilon_(0)A)/(d)`
`=(8.85xx10^(-12)xx1)/(10^(-3))`
`=8.85xx10^(-9)`
So, `C=8.85" nF"`