Four capacitors whose capacitances are indicated in `muF` are connected in the circuit given below. Calculate the equivalent capacitance between the point A and B.

Explanation

Here, `2muF` and `2muF` capacitors are in parallel.
So, `C_("eq")^(.)=2+2=4muF`
Now, `C_("eq")^(.)` is in series with `1muF` and another `1muF` capacitors.
`:." "(1)/(C_("eq"))=1/1+1/1+1/4=9/4`
`:." "C_("eq")=(4)/(9)=0.44muF`
Hence, the equivalent capacitance between points A and B will be `0.44muF`.