How can we connect three capacitors of `3muF,3muF` and `6muF` such that their equivalent capacitance will be `5muF` ?

Explanation

Here, `C_("max")=3+3+6=12muF`
and `(1)/(C_("min"))=1/3+1/3+1/6=(2+2+1)/(6)`
`rArr" "C_("min")=6/5=1.2muF`
The required equivalent capacitance of `5muF` lies between `C_("max")" and "C_("min")`.
So, `5muF=3muF+2muF=3muF+(1)/(1/3+1/6)muF`
So, we must connect `3muF` and `6muF` capacitors in series first, then in parallel with third capacitor of capacitance `3muF`.