A copper wire of `2.5 xx 10^(-6) m^(2)` area carries a current of `1.6` A. If the number density of the electrons in the wire is `8 xx10^(28)//m^(3)` , then calculate the drift speed of the electrons in the wire . (Take `e = 1.6 xx 10^(-6)C)`

Explanation

Given, area `a = 2.5 xx10^(-6) m^(2)`
Current , I = 1.6 A
Number density of electrons , `n = 8 xx10^(28)//m^(3)`
` :. " " I = "ne"Av_(d)`
` :. " "v_(d) = I/("neA")`
`=(1.6)/(8xx10^(28)xx1.6xx10^(-19)xx2.5 xx10^(-6))` (1)
`v_(d) = 0.05 xx10^(-3)`
` :. `Drift velocity `v_(d)= 5xx10^(-5) m//s ` (1)