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A proton which carries a charge of 1.6xx...

A proton which carries a charge of `1.6xx10^(-19)` C moving with a velocity of `2xx10^(6)` m/s enters a uniform magnetic field of intensity 350 `Wbm^(-2)` at right angle to it. Calculate the magnitude of force experienced by the particle.

Text Solution

Verified by Experts

Given, `q=1.6xx10^(-19)C,v=2xx10^(6)m//s`,
`B=350Wbm^(-2),theta=90^(@),|F|=?`
Now, magnitude of force,
`F=qvBsintheta`
= `1.6xx10^(-19)xx2xx10^(6)xx350xx1`
`32xx35xx10^(-13)`
`1120xx10^(-13)`
So, `|F|=1.12xx10^(-10)N`
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