Given that a photon of light of threshold wavelength `1000Å` and intensity `I_(0)` falls in a photoelectric cell. If the saturating current is `0.40xx10^(-6)` A and the stopping potential is `1.36` V. Then, the work function is

Options

A. `0.43` eV
B. `12.4` eV
C. `1.36` eV
D. `2.47` eV

Answer

B

Explanation

The work function is given by
`φ=(hc)/(lamda_(0))=(6.63xx10^(-34)xx3xx10^(8))/(1000xx10^(-10)xx1.6xx10^(-19))`
`12.4 eV`