Calculate the de-Broglie wavelength of a proton having kinetic energy 50 Ev.
(`m_(p)=1.67xx10^(-27)kg,h=6.62xx10^(-34)J-s`)

Explanation

As we know, `lamda=h/(p)`
and `p=sqrt(2Km)`
Where, K = kinetic energy and m = mass,
So, `lamda=(6.62xx10^(-34))/(sqrt(2xx50xx1.6xx10^(-19)xx1.67xx10^(-27)))`
`=(6.62xx10^(-34))/(sqrt(267.2xx10^(-46)))=(6.62xx10^(-34))/(16.34xx10^(-23))=0.405xx10^(-11) m`