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Given the electronic charge, e = 1.6 xx ...

Given the electronic charge, `e = 1.6 xx 10^(-19)C, electronic mass, `m = 9.1 xx 10^(-19) kg, h = 6.6 xx 10^(-34) J-s` and `c = 3 xx 10^8 m//s`
The radius of the first orbit of electron in hydrogen atom is

A

`5.3 xx 10^1Å`

B

`5.3 xx 10^0 Å`

C

`5.3 xx 10^(-1) Å`

D

`5.3 xx 10^(-2) Å`

Text Solution

Verified by Experts

The correct Answer is:
C
The radius of first orbit is given as
` r_1 = (h^2 epsi_0)/(pi me^2)`
Substituting given values, we get
` r_1 = ((6.6 xx 10^(-34) )^2 xx (8.85 xx 10^(-12) ) )/(3.14 xx (9.1 xx 10^(-19) ) xx (1.6 x 10^(-19))^2)`
` = 0.53Å or 5.3 xx 10^(-1) Å`
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