Half-life of a radioactive sample is 2h. What fraction of sample will decay in 8 h?

Explanation

Using, `N=N_(0)(1/2)^(n)`
We get, `N=N_(0)/2^(n)=N_(0)/2^(4)=N_(0)/16` [`because` 8h cover 4 half-lives]
`thereore` Decayed sample = `N_(0)-N=15/16N_(0)`
`rArr` Fraction decayed of sample `=(N_(0)-N)/N_(0)=15/16`