A parallel plate capacitor is connected to as 5 V battery and charged. The battery is then disconnected and a glass slab is introduced between the plates. Then, the quantities that will decrease are

Options

A. charge and potential difference
B. charge and capacitance
C. capacitance and potential difference
D. energy stored and potential difference

Answer

D

Explanation

Since, `U=1/(2)(q^(2))/(KC)andV=q/(KC)`
where, K is dielectric constant.