For any frequency distribution, mean is always greater than mode.

For a frequency distribution, mean, median and mode are connected by the relation . . . . .

If the mode of a frequency distribution exceeds its mean by 12, then the mode exceeds its median by . . . .

For a given frequency distribution, median = 13.2 and mean = 15.3. Then by the relation between mean, median and mode, mode = . . . . . .

Given below is a frequency distribution of daily income of 100 workers of a factory : {:("Daily income of workers (in ₹) ","Number of workers "),(" "200-300," "12),(" "300-400," "18),(" "400-500," "35),(" "500-600," "20),(" "600-700," "15):} Convert this distribution to cumulative frequency distribution of more than type and less than type

Find the mean and standard deviation for the following frequency distribution: The follwing table gives the income of 100 families . Find the variance for the data.

The median of a given frequency distribution is found graphically with the help of . . . . .

For the frequency distribution: Find the standard distribution .

For a frequency distribution, Mode-Median = . . . . . xx (Median-Mean)

For any event A, P (A) is always greater than P(barA) .

Explain -"for photoelectric emission frequency of incident radiation should be greater than threshold frequency".