A train starting from a railway station and moving with uniform acceleration attains a speed of `40 km ^(-1)` in 10 minute. Find its acceleration.

Explanation

Here, initial speed `(u) = 0 ms ^(-1),`
`t = 10` minute `=600s `
Final velocity `(v) = 40 km h ^(-1) =(40 xx 1000)/(3600) = (100)/(9) ms ^(-1)`
Acceleration `= (v0u)/(t)= (( 100)/(9) - 0)/( 600) = (100)/( 9 xx 600) = (1)/( 54) m s^(-1)`
The acceleration is `(1)/(54) ms ^(-2).`