An object starting from rest undergoes an acceleration of `8ms ^(-2)`for 10 second. Find (a) the speed (b) the distance travelled.

Explanation

`u =0, a =8 ms ^(-2), t =10` second
`(a) v =u +at`
`=0 + 8 ms ^(-2) xx 10s `
`= 80 ms ^(-1) " "..(1)`
` (b) s = ut + (1)/(2) at ^(2)`
` = 0 xx 10 + (1)/(2) xx 8 ms ^(-2) xx (10 s ) ^(2) `
`=0 + 4 xx 100 m = 400 m " "...(2)`
The speed of the object is `80 ms ^(-1),` the distance travelled by the object is 400 m.