A motorcycle moving with a speed of `5 ms^(-1)` is subjected to an acceleration of `0.2 ms^(-2)` for 10 second. Calculate (a) the speed (b) the distance travelled.

Explanation

Here,` u = 5 ms ^(-1),a =0.2 ms ^(-2), t = 10` second
`(a) v = u + at `
`= 5 ms ^(-1) + 0.2 ms ^(-2) xx 10 s `
` = 5 ms ^(-1) + 5 ms ^(-1) = 10 ms ^(-1)`
(b)` s = ut + 1/2 at `
`= 5 ms ^(-1) + 10s + 1/2 xx 0.2 ms ^(-2) xx (10 s ) ^(2)`
`= 50 m + 10 m = 60 m`
The speed of the motorcycle after 10 second is `10 ms ^(-1),` the distance travelled by the motorcycle is 60 m.