If a constant force is applied to an object of mass 0.9 kg in stationary state for 10s, it covers distance of 250m, what magnitude of this force would be?

Options

A. 18 N
B. 13.5 N
C. 9N
D. 4.5 N

Answer

D

Explanation

`s=ut+(1)/(2)at^(2)=ut+(1)/(2)((F)/(m))t^(2)`
Now,
u=0,m=0.9 kg,t=10s,s=250m
Som `250=0+(1)/(2)((F)/(0.9))(10)^(2)`
`therefore F=((250)(0.9))/(100)=4.5N`
4.5 N