Two hockey players of opposite teams,while trying to hit a hockey collide and immediately become entangled .One has a mass of 60 kg velocity 5.0 m`s^(-1)` while the other has a mass of 55 kg and was moving faster with a velocity 6.0 `ms^(-1)` the first player .In which direction and with what velocity will they move after they become entangied?Assume that the frictional force acting between the feet of the two plyaers and ground is negligible.

Explanation

Let the first player .be moving from left to right.By covention left to right is take as positive direction and thus right to left is the negative direction .
If symbols m and u represent the mass and initial velocity of the two players respectively.Subscripts 1 and 2 in these physical quantities refer to the two hockey players .
Thus, `m_(1)=60 kg,u_(2)=+5 ms^(-1)` and
`m_(2)=55 kg ,u_(2)=-6 ms^(-1)`
The total momentum of the two players before collision . If v is the velocity of the two entanged players after the collision ,the total momentum
`=(m_(1)+m_(2))xxv` `115xxvkgms^(-1)`
Equating the momenta of the system befor and after collision,in accordance with the law of conservation of momentum we get
`v=(-30)/(115)=-0.26 ms^(-1)`
Thus the two entangled players would move with velocity o.26 m `s^(-1)` from right to left.That is, in the direction the second player was moving before the collision.