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A stone of 1 kg is thrown with a velocit...

A stone of 1 kg is thrown with a velocity of 20 m`s^(-1)` across the frozen surface of a lake and comes to rest after travelling a distance of 50 m.What is the force of friction between the stone and the ice?

Text Solution

Verified by Experts

Here,m1 kg,u=20 m`s^(-1)`,s=50 m,v=0
F=?,a=?
`v^(2)-u^(2)=2as`
`therefore (O)^(2)-(20)^(2)=2axx50`
`therefore -400=100a`
`therefore=(-400)/(100)`
`therefore =-4 ms^(-2)`
Force of friction F=ma
`1xx(-4)`
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