Home
Class 9
PHYSICS
A bulllet of mass 10 g travelling horizo...

A bulllet of mass 10 g travelling horizontally with a velocity of 150 m`s^(-1)` strickes a stationaty wooden block and comes to rest in 0.03 s.Calculate the distance of penertaton magnitude of the force exerted by the wooden block on the bullet.

Text Solution

Verified by Experts

Here,m=10g-0.01 kg,
u=150 m`s(-1)` ,v=0,t=0.03 s
`a=(v-u)/(t)=(0-150)/(0.03) ms^(-2)=-5000 ms^(-2)`
The distance of penetration of the bullet into the block.
`s=ut+(1)/(2)at^(2)`
`=150xx0.3+(1)/(2)xx(-5000)xx(0.03)^(2)` The magnitude of the force exerted by the wooden block on the bullet.
The distance of penetration is 2.25 m.The magnitude of force is 50N.
Promotional Banner

Topper's Solved these Questions

  • FORCE AND LAWS OF MOTION

    KUMAR PRAKASHAN|Exercise Additional Exercise|4 Videos

  • FORCE AND LAWS OF MOTION

    KUMAR PRAKASHAN|Exercise Additional Numericals for Practice|18 Videos

  • FORCE AND LAWS OF MOTION

    KUMAR PRAKASHAN|Exercise QUESTIONS AND ANSWERS(Solve the following examples/numericals :)|8 Videos

  • GRAVITATION

    KUMAR PRAKASHAN|Exercise ACTIVITY 10.4|2 Videos

Similar Questions

Explore conceptually related problems

A bullet of mass 0.04 kg moving with a speed of 90 m s^(-1) enters a heavy wooden block and is stopped after a distance of 60 cm. What is the average resistive force exerted by the block on the bullet?

A bullet of m ass 10 g m oving horizontal w ith a velocity of 400 ms^(-1) strikes a w ood block of m a ss 2 kg w h ic h is s u s p e n d e d by lig h t inex ten sib le strin g of length 5 m. As resu lt the c e n tre of gravity of th e block fo und to rise a v ertical distan ce of 10 cm . The sp eed of the bullet after it em erges on horizontally from the block will b e ......

A bullet of mass 0.012kg and horizontal speed 70 ms^(-1) strikes a block of wood of mass 0.4kg and instantly comes to rest with respect to the block. The block is suspended from the ceiling by means of thin wires. Calculate the height to which the block rises. Also, estimate the amount of heat produced in the block.

A block of mass m_(1) = 1 kg is horizontally thrown with a velocity of v = 10 m//s on a statonary long plank of mass m_(2) = 2 kg whose surface has mu = 0.5 plank rest on frictionless surface find the time when the block comes to rest w.r.t plank

Two blocks of masses 2kg and M are at rest on an inclined plane and are separated by a distance of 6.0m as shown. The coefficient of friction between each block and the inclined plane is 0.25 . The 2kg block is given a velocity of 10.0m//s up the inclined plane. It collides with M, comes back and has a velocity of 1.0m//s when it reaches its initial position. The other block M after the collision moves 0.5m up and comes to rest. Calculate the coefficient of restitution between the blocks and the mass of the block M. [Take sintheta=tantheta=0.05 and g=10m//s^2 ]