An object of mass 100 kg is accelerated uniformly from a velocity of 5 `ms^(-1)` to 8 m `s^(-1)` in 6 s of the object.Find the magnitude of the force exerted on the object.

Explanation

Here,m=100kg u= 5 m`s^(-1)`
v=8 m`s^(-1)`,t=6s
Initial momentum `P_(1)=mu=100xx5`
500 kg `ms^(-1)`
Final momentum `P_(2)=mv=100xx8`
800 kg `ms^(-1)`
Force exerted on the object.
F=ma Initial momentum is 500 kg `ms^(-1)` final momentum is 800 kg m`s^(-1)`.The magnitude of force exerted on the object is 50N