The increase in velocity of a freely falling body in one second is

Options

A. `9.8 ms^(-2)`
B. `9.8 ms^(-1)`
C. `-9.8 ms^(-2)`
D. `-9.8 ms^(-1)`

Answer

A

Explanation

Acceleration of the freely falling body is always equal to gravitational acceleration `9.8 ms^(-1)` That means velocity of freely falling body increases by `9.8 ms^(-1)` per second. Initial velocity of freely falling body is always zero. So after 1 second its velocity becomes `9.8 ms^(-1)` .