What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface ?
(Mass of the earth is `6 xx 10^(24)` kg and radius of the earth is `6.4 xx 10^(6) m)`

Answer

The magnitude of the gravitional force between the earth and a 1kg object is 9.8N.

Explanation

Here, mass (m) of the body =1kg mass `(M_e)` of the earth `=6 xx 10^(24)kg`, radius `(R_(e))` of the earth `=6.4 xx 10^(6)m`.
Magnitude of the gravitional force between the earth and 1kg object.
`F=G ""(M_(e)m)/(R_(e)^(2))=(6.67xx 10^(-11) xx 6 xx 10^(24) xx1)/((6.4 xx 10^(6))^(2))`
`=(6.67 xx 10^(13))/(6.4 xx 6.4 xx 10^(12))`
`=(6.67 xx 6 xx 10)/(6.4 xx 6.4) =9.77N approx 9.8N`