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A stone is released from the top of a to...

A stone is released from the top of a tower of height 19.6m. Calculate its final velocity just before touching the ground.

Text Solution

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The correct Answer is:
The magnitude of the final velocity is `19.6ms^(-1)`.
Here, `u=0, g=+9.8ms^(-2), s=+19.6m`
`v^(2)-u^(2)=2gs`
`v^(2)-0=2 xx (+9.8) xx (19.6)`
`v^(2)=19.6 xx 19.6`
`v=pm 19.6ms^(-1)`
Here, `v=+19.6ms^(-1)` because the final velocity is in the downward direction.
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Knowledge Check

  • A stone is dropped from the top of tower. If its velocity at the mid point of height of tower is 10ms^(-1), then the height of a tower is ..... (g = 10 ms^(-2))

    A
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    B
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    C
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