Find the average density of the earth in the terms of g. G and `R_e`.

Answer

Density `Q=(3g)/(4pi R_(e)G)`

Explanation

The gravitional acceleration on the earth.s surface.
`g=(GM_(e))/(R_(c)^(2)) therefore M_(C)=(g R_(e)^(2))/(G)`
Density Q `=("Mass "(M_(e)))/("Volume (V)")`
`=(M_(e))/((4/3 pi R_(e)^(3))`
`=(3)/(4pi R_(e)^(3)) xx (g R_(e)^(3))/(G)`
`=(3g)/(4pi R_(e)G)`