A cube of length 5 cm is immersed first in water and then in common salt solution. In which case would the buoyant force be more on the cube? Why?
Now, if the length of the cube is made 4 cm and immersed in water, then in this new case what would be the effect on buoyant force on the cube as compared to the first case of water ?

Answer

In salt solution because density of salt solution is more than the simple water. In new case, buoyant force acting on cube in water would be less compared to first case.

Explanation

The density of common salt solution is more than fresh water, there would be more buoyant force on the cube in salty water as compared to fresh water.
In new case, the buoyant force on the cube in water would be less than that in first case, because in new case the volume of the cube is decreased.