Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of `60kmh^(-1)`.

Answer

The work required to be done to stop the car is 208333.3 J, which is done by the braking force.

Explanation

Here, `m=1500kg`,
`v=60kmh^(-1)=60xx(5)/(18)ms^(-1)=(50)/(3)ms^(-1)`, findla velocity is zero.
`therefore` Work required to stop the car
= change in K.E. of the car
`=(1)/(2)mv^(2)-(1)/(2)m(0)^(2)`
`=(1)/(2)mv^(2)`
`=(1)/(2)xx1500xx((50)/(3))^(2)J`
`=(1)/(2)xx1500xx(50)/(3)xx(50)/(3)J`
`~~208333.3J`