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The distance between two consecutive con...

The distance between two consecutive conden sations in the sound wave propagating in air is im. If the velocity of the sound in air is 340 `ms^(-1)`, what would be the frequency of this wave?

A

680 Hz

B

340 Hz

C

170 Hz

D

85 Hz

Text Solution

Verified by Experts

Wavelength `lambda` = Distance between
two consecutive
condensations
=2m
Frequency `v=(u)/(lambda)=(340)/(2)=170 Hz`
170 Hz
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