cos (540^(@)-theta)-sin (630^(@)-theta) ...

`cos (540^(@)-theta)-sin (630^(@)-theta)` is equal to

A

0

B

`2cos theta`

C

`2 sin theta`

D

`sin theta-cos theta`

Text Solution

Verified by Experts

The correct Answer is:

a

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Knowledge Check

If sin theta = cos (20^(@)+theta) , then theta is equal to :

A

25

B

35

C

28

D

30

If tan theta = (12)/(13) , then (2 sin theta cos theta)/(cos^(2) theta - sin^(2) theta) is equal to

A

`(123)/(25)`

B

`(312)/(25)`

C

`(231)/(25)`

D

`(192)/(25)`

(cos 3 theta)/(cos^(3)theta)+(sin 3 theta)/(sin^(3)theta) is equal to

A

`3cos2theta"cosec" theta`

B

`2cot2theta"cosec"2theta`

C

`12cot 2 theta"cosec" 2 theta`

D

`12 tan 2theta sec 2 theta`

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