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If cos theta=cos alpha cos beta, then "t...

If `cos theta=cos alpha cos beta`, then `"tan"(theta+alpha)/(2)"tan"(theta-alpha)/(2)` is equal to

A

`tan^(2) (alpha//2)`

B

`tan^(2)(beta//2)`

C

`tan^(2)(theta//2)`

D

`cot^(2)(beta//2)`

Text Solution

Verified by Experts

The correct Answer is:
b
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