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If cos alpha+cos beta = a, sin alpha+sin...

If `cos alpha+cos beta = a, sin alpha+sin beta=b and a-beta=2 theta,` then `(cos 3theta)/(cos theta)=`

A

`a^(2)+b^(2)-2`

B

`a^(2)+b^(2)-3`

C

`3-a^(2)-b^(2)`

D

`(a^(2)+b^(2))//4`

Text Solution

Verified by Experts

The correct Answer is:
b
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