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If sin theta+cos theta=a and cos theta-s...

If `sin theta+cos theta=a and cos theta-sin theta=b` then `sin theta(sin theta-cos theta)+sin^(2)theta(sin^(2)theta-cos^(2)theta)+sin^(3)theta(sin^(3)theta-cos^(3)theta)+…` is equal to

A

`(1-ab)/(1+ab)`

B

`(1-a^(2))/(3-a^(2))`

C

`(1-ab)/(1+ab) +(1-a^(2))/(3-a^(2))`

D

`(1+ab)/(1-ab)-(a^(2)-1)/(3-a^(2))`

Text Solution

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The correct Answer is:
c
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