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ABCD is a trapezium such that AB and CD ...

ABCD is a trapezium such that AB and CD are parallel and `BC bot CD`. If `angleADB=theta, BC=p and CD=q`, then AB is equal to

A

`(p^(2)+q^(2)cos theta)/(p cos theta+ q sin theta)`

B

`(p^(2)+q^(2))/(p^(2)cos theta+q^(2)sin theta)`

C

`((p^(2)+q^(2))cos theta)/((p cos theta+q sin theta)^(2))`

D

`((p^(2)+q^(2))sin theta)/(p cos theta+q sin theta)`

Text Solution

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The correct Answer is:
d
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