Which one is wrong combination?

Options

A. Mollusca.- Pila (Apple snail), Chaetopleura (Chiton)
B. Echinodermata - Echinus (Sea urchin), Antedon (Sea lily), Cucumaria (Şea cucumber)
C. Echinodermata - Spiny bodied
D. None

Answer

To determine which combination is wrong, we need to analyze each option provided in the question.

### Step-by-Step Solution:

1. **Analyze Option 1**:
- The term "molaska paila" refers to "Mollusca," which is a phylum.
- "Ketoclura" is mentioned as being known as "apple's nail," which is a common name for certain mollusks.
- "Ketoclura" belongs to the class "Amphineura" within the phylum Mollusca.
- Therefore, this option is a correct combination.

**Hint**: Check if the scientific names and their classifications match the known taxonomy.

2. **Analyze Option 2**:
- "Ikainuda meta" refers to "Echinodermata," which is another phylum.
- "C archi" is likely referring to "Asteroidea," which is the class that includes starfish, also known as "Aristotle's lantern."
- "Lili" and "kukumaria" are common names for certain echinoderms, likely referring to sea cucumbers.
- This option is also a correct combination.

**Hint**: Verify if the common names correspond to the correct scientific classifications in the phylum Echinodermata.

3. **Analyze Option 3**:
- This option states that members of "Ikainuda meta" (Echinodermata) have spines on their bodies.
- Starfish, which are members of the class Asteroidea, do indeed have spines on their arms.
- Therefore, this statement is also correct.

**Hint**: Consider the physical characteristics of the organisms mentioned to confirm their classification.

4. **Analyze Option 4**:
- This option states "none," implying that there is no wrong combination among the previous options.
- Since all previous options have been verified as correct, this option is indeed the correct answer.

**Hint**: If all previous options are correct, then the answer indicating no wrong combinations must be true.

### Conclusion:
After analyzing all the options, we find that there are no wrong combinations. Therefore, the answer is **Option 4: None**.