To determine which phase lasts for more than 95% of the duration of the cell cycle, we can analyze the different phases of the cell cycle, which include G1, S, G2, and M phases.
### Step-by-Step Solution:
1. **Understanding the Cell Cycle**: The cell cycle consists of several phases: G1 (Gap 1), S (Synthesis), G2 (Gap 2), and M (Mitosis). Each of these phases has a different duration.
2. **Identifying the Phases**:
- **G1 Phase**: This is the first gap phase where the cell grows and prepares for DNA synthesis.
- **S Phase**: This is the synthesis phase where DNA replication occurs.
- **G2 Phase**: This is the second gap phase where the cell prepares for mitosis.
- **M Phase**: This is the mitotic phase where cell division occurs.
3. **Analyzing Duration**:
- The transcript mentions specific durations for G1, S, and G2 phases, which together form the interphase.
- The durations are as follows:
- G1: 11R
- S: 7R
- G2: 4R
- The M phase is significantly shorter, lasting only 2R.
4. **Calculating Total Duration**:
- Total duration of interphase (G1 + S + G2) = 11R + 7R + 4R = 22R
- Total duration of the cell cycle = Interphase + M phase = 22R + 2R = 24R
5. **Finding the Percentage of Time Spent in Each Phase**:
- Percentage of time spent in interphase = (Duration of interphase / Total duration) * 100
- Percentage of time spent in interphase = (22R / 24R) * 100 = 91.67%
- Since 91.67% is less than 95%, we need to consider that the interphase (G1, S, G2) collectively lasts for the majority of the cell cycle.
6. **Conclusion**: The interphase (G1, S, G2) lasts for more than 95% of the duration of the cell cycle, as it encompasses the majority of the time before the cell enters the M phase.
### Final Answer:
The phase that lasts for more than 95% of the duration of the cell cycle is the **interphase** (which includes G1, S, and G2).
