If in a cell 6 tetrad are present in prophase-I then what will be the number of chromatids in each cell in Anaphase-II?

Options

A. 24
B. 6
C. 12
D. 48

Answer

To solve the question regarding the number of chromatids in a cell during Anaphase II, given that there are 6 tetrads present in Prophase I, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Tetrads**:
- A tetrad is formed during Prophase I of meiosis when homologous chromosomes pair up. Each tetrad consists of 4 chromatids (2 from each homologous chromosome).

2. **Calculating Chromatids in Prophase I**:
- Since there are 6 tetrads present, we can calculate the total number of chromatids:
\[ \text{Total chromatids} = \text{Number of tetrads} \times \text{Number of chromatids per tetrad} = 6 \times 4 = 24 \text{ chromatids} \]

3. **Meiosis Progression**:
- During Meiosis, the cell undergoes two rounds of division: Meiosis I and Meiosis II.
- In Meiosis I, the homologous chromosomes (tetrads) are separated into two daughter cells. Each daughter cell will have half the number of chromatids.

4. **Chromatid Count After Meiosis I**:
- After Meiosis I, each of the two daughter cells will have:
\[ \text{Chromatids in each cell} = \frac{24}{2} = 12 \text{ chromatids} \]

5. **Anaphase II**:
- In Anaphase II, the sister chromatids of each chromosome are separated. Since each daughter cell from Meiosis I has 12 chromatids, these will be separated into individual chromatids during Anaphase II.

6. **Final Count of Chromatids in Anaphase II**:
- Therefore, in each cell during Anaphase II, there will still be 12 chromatids, as they are simply being separated from each other.

### Conclusion:
The number of chromatids in each cell during Anaphase II is **12**.

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