If a plasmolysed cell has OP = 10, TP = -2, its DPD will be -

Options

A. 8
B. 12
C. 10
D. None of these

Answer

To solve the question regarding the diffusion pressure deficit (DPD) of a plasmolysed cell with given osmotic pressure (OP) and turgor pressure (TP), we can follow these steps:

### Step-by-step Solution:

1. **Understand the Definitions**:
- **Osmotic Pressure (OP)**: This is the pressure required to prevent the flow of water into a solution via osmosis. It is a measure of the concentration of solutes in the solution.
- **Turgor Pressure (TP)**: This is the pressure exerted by the fluid (usually water) inside the cell against the cell wall. It is a measure of the cell's internal pressure.
- **Diffusion Pressure Deficit (DPD)**: This is defined as the difference between the osmotic pressure and the turgor pressure. The formula is:
\[ \text{DPD} = \text{OP} - \text{TP} \]

2. **Substitute the Given Values**:
- From the question, we have:
- OP = 10
- TP = -2
- Substitute these values into the DPD formula:
\[ \text{DPD} = 10 - (-2) \]

3. **Calculate DPD**:
- Simplifying the equation:
\[ \text{DPD} = 10 + 2 = 12 \]

4. **Final Result**:
- Therefore, the DPD of the plasmolysed cell is **12**.

### Final Answer:
The DPD will be **12**.