Which one is correct?

Options

A. Kreb's cycle and chemiosmosis are inhibites in anaerobic conditions
B. Both glucose and fructose readily enter the glycolytic pathway
C. Glucose and fructose are phosphorylated by Hexokinase
D. All

Answer

To determine which statement is correct regarding respiration in plants, we need to analyze each option provided in the question.

### Step-by-Step Solution:

1. **Understanding Anaerobic Conditions**:
- In anaerobic conditions, oxygen is not available for respiration. Under these conditions, only glycolysis can occur.
- The Krebs cycle (also known as the citric acid cycle) and oxidative phosphorylation (which includes the electron transport chain) cannot take place without oxygen.

**Conclusion**: Option 1 states that the Krebs cycle and chemiosmosis are inhibited by anaerobic conditions. This is correct.

2. **Glycolytic Pathway**:
- Glycolysis is the metabolic pathway that converts glucose into pyruvate, producing ATP in the process.
- Both glucose and fructose can enter the glycolytic pathway. Fructose can be converted into glucose by the action of isomerase enzymes present in the cytoplasm.

**Conclusion**: Option 2 states that both glucose and fructose can enter the glycolytic path. This is also correct.

3. **Phosphorylation by Hexokinase**:
- Hexokinase is an enzyme that phosphorylates hexose sugars, which include both glucose and fructose.
- When glucose enters the pathway, it is phosphorylated to glucose-6-phosphate. Fructose can also be phosphorylated to fructose-1-phosphate by fructokinase, which is a specific kinase for fructose.

**Conclusion**: Option 3 states that glucose and fructose are phosphorylated by hexokinase. This statement is partially correct because while hexokinase does phosphorylate glucose, fructose is typically phosphorylated by fructokinase.

4. **Final Assessment**:
- After analyzing all three options, we find that:
- Option 1 is correct.
- Option 2 is correct.
- Option 3 is partially correct but misleading as it does not mention that fructose is phosphorylated by a different enzyme.

### Final Answer:
The correct statements are:
- Option 1: Krebs cycle and chemiosmosis are inhibited by anaerobic conditions.
- Option 2: Both glucose and fructose can enter the glycolytic path.